表示日期,很方便。datetime.datetime(), datetime.date(), datetime.timedelta()
>>> d1 = datetime.date(2001,6,7)
>>> d2 = datetime.date(2008,8,5)
>>> d = datetime.date(2006,7,7)
>>> if d1 <= d <= d2:
... print 'good'
...
good
>>> delta = d2-d1
>>> delta.total_seconds()
226022400.0
>>> d = datetime.date.today()
>>> d
datetime.date(2011, 6, 24)
>>> d.year, d.month, d.day
(2011, 6, 24)
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